| SCI 270: On Nuclear Technology Practice Problems |
Answers are given for your reference only. Please do your part of
the learning, because no one else will be able to do that for you.
Your skills of problem solving are tested and useful in the future. Answers are useless. Acquiring skills and abilities are the goals of learning, marks indications of your performances on these tasks.
Please use 1e-6 to mean 10-6 in your expressions.
|Rest mass in J||Rest mass in MeV||g||kg||amu|
|Charge in C||Charge in esu||Spin||Magnetic moment|
|-1.6022e-19||-4.8066e-10||½||9.28477e-24 J T-1|
|Charge for one mole of electron F =||96485.31 C|
|Avogadro's number NA =||6.0221e23 particle mol-1|
|Give the formula and result you use to|
estimate the charge per electron from F
|F/NA = 1.6022e-19 C|
|The Planck constant||h = 6.62619e-34 J s-1|
|Kinetic energy in J =||1.602197e-19 J (=C V)|
|Velocity of the electron||(2E/m)1/2 = 5.931e5 m/s|
|Force = 8.2158e-8 N (a small force)
Note F = C q1 q2 / r2
C = 8.98755e9 N m2C-2
or F = q1 q2 / 4p eo r2
eo = 8.85e-12 N-1 m-2C2
p = 3.141592; Some browser cannot produce pi.
q = e = 1.6022e-19 C
|36 g water =||2 mol|
|Number of molecules in 36 g water =||1.20442e24 molecules||2 NA|
|Number of atoms in 36 g water =||3.61326e24 atoms||6 NA|
|Energy =||2.962e21 keV||4 F * 1.23|
|Energy required to decompose|
a water molecule
|2.46 eV||2*1.23 eV|