The mass action law is valid for the case when the solvent is a reactant
or product. However, due to the large amount of solvent present, the
equilibrium constant expression can be simplified.
Special consideration also apply to heterogeneous equilibria, in which, solids or liquids are involved. Phases such as liquid and solid are not sensitive to pressure, and their "concentration" are constant as long as these phases are present. Their "concentrations" are not defined, and that is why we use a " " to mark the special meaning of these phases. Perhaps "activity" or "property" is a better term to use than "concentration" in these cases.
For example, when water is used as a solvent, the concentration of water is almost always a constant. Its concentration can be calculated to be 55.6 M. (1 L of water has 1000 g, and molecular weight 18 g/mol; and thus [H2O] = 1000/18 = 55.6 mol/L)
For example, consider the following reaction,
[CH3COOC2H5] [H2O]
K' = -------------------
[CH3COOH] [C2H5OH]
or
[CH3COOC2H5]
K = -------------------
[CH3COOH] [C2H5OH]
Of course, K = K' / [H2O] = K' /55.6
In heterogeneous equilibria, the activities (or concentrations) of solid and liquid but not gas are always a constant. In these cases, their activities or concentrations are omitted in the expression of Q or K.
Let us look at these expressions for the equilibria:
Hint 55.6
Consider...
For most solutions, [H2O] = 1000 / 18 = ?
Hint P(O2)
Consider...
This reaction is used to produce O2 from HgO.
Hintr 0.031 atm
Consider...
Kp = P(H2O) in this case.
Just want you to consider one of the common equilibrium state.
The amount of water present does not affect the vapor pressure.
Answer 0.3
Consider...
CH3COOC2H5(aq) + H2O(l) = CH3COOH(aq) + C2H5OH(aq)
0.9 x x
x2 / 0.90 = K = 0.1; x = ?
Answer 9
Consider...
P(HCl) = square root (Kp)
NH4Cl(s) = NH3(g) + HCl(g).
x x
Kp = x2