CAcT HomePage
The Clausius-Clapeyron Equation
Skills to develop
- Apply the Clausius-Clapeyron equation to estimate the vapor
pressure at any temperature.
- Estimate the heat of phase transition from the vapor pressures
measured at two temperatures.
The Clausius-Clapeyron Equation
The vaporization curves of most liquids have similar shape. The
vapour pressure steadily increase as the temperature increases.
A good approach is to find a mathematical model for the pressure increase
as a function of temperature. Experiments showed that the pressure P,
enthalpy of vaporization, DHvap,
and temperature T are related,
P = A exp (- DHvap / R T)
where R (= 8.3145 J mol-1 K-1) and A are
the gas constant and unknown constant. This is known as the Clausius-
Clapeyron equation. If P1 and P2
are the pressures at two temperatures T1 and
T2, the equation has the form:
P1 DHvap 1 1
ln (---) = ---- (--- - ---)
P2 R T2 T1
The Clausius-Clapeyron equation allows us to estimate the vapor pressure
at another temperature, if the vapor pressure is known at some temperature,
and if the enthalpy of vaporization is known.
Example 1
The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of
vaporization is 40.7 kJ mol-1. Estimate the vapor pressure at
temperature 363 and 383 K respectively.
Solution
Using the Clausius-Clapeyron equation, we have:
P363 = 1.0 exp (- (40700/8.3145)(1/363 - 1/373)
= 0.697 atm
P383 = 1.0 exp (- (40700/8.3145)(1/383 - 1/373)
= 1.409 atm
Note that the increase in vapor pressure from 363 K to 373 K is 0.303 atm,
but the increase from 373 to 383 K is 0.409 atm. The increase in vapor
pressure is not a linear process.
Discussion
We can use the Clausius-Clapeyron equation to construct the entire
vaporization curve. There is a deviation from experimental value, that
is because the enthalpy of vaporization various slightly with temperature.
The Clausius-Clapeyron equation applies to any phase transition. The following
example shows its application in estimating the heat of sublimation.
Example 2
The vapor pressures of ice at 268 and 273 are 2.965 and 4.560 torr respectively.
Estimate the heat of sublimation of ice.
Solution
The enthalpy of sublimation is
DHsub.
Use a piece of paper and derive the Clausius-Clapeyron equation
so that you can get the form:
DHsub
= R ln (P268 / P268)
(1/268 - 1/273)
= 8.3145*ln(2.965/4.560) / (1/268 - 1/273)
= 52370 J mol-1
Note that the heat of sublimation is the sum of heat of melting
and the heat of vaproization.
Discussion
Show that the vapor pressure of ice at 274 K is higher than that of water
at the same temperature.
Note the curve of vaporization is also called the curve of evaporization.
Confidence Building Questions
©cchieh@uwaterloo.ca