Dimond crystals such as the one shown here is appreciated by almost everyone,
because of their hardness, sparkle, and high value. They are also important
in many technical applications. However, in terms of chemistry, diamonds
consist of only carbon atoms, except impurities. Like diamond, the chemistry
of carbon is indeed very interesting and valuable.
Carbon atoms have the ability to bond to themselves and to other atoms with sp, sp2, and sp3, hybrid orbitals. This link gives you the basics about the hybrid orbitals, and you are introduced to the various bonding of carbon in this document.
Compounds containing carbon-hydrogen bonds are called organic compounds. May also contain C-C, C=C, CºC, C-N, C=N, CºN, C-O, and C=O bonds. Such a variety is due to the ability of carbon to make use of sp, sp2, and sp3 hybrid orbitals for the bonding. There are also various inorganic compounds such as carbon monoxide, carbon dioxide, calcium carbonate, sodium bicarbonate, etc. involving carbon.
Note that molecules H-CºC-H, H-CºN, and CºO have the same number of electrons. Bonding in these molecules can be explained by the same theory, and thus their formation is no surprise. The O=C=O molecule is linear, and the carbon atom in this molecule also involve the sp hybrid orbitals. Two pi bonds are also present in this simple molecule. As an exercise, draw a picture to show the two sigma and two pi bonds for this molecule.
When carbon atoms make use of sp2 hybrid orbitals for sigma
bonding, the three bonds lie on the same plane. One such compund is ethene,
in which, both carbon atoms make use of sp2 hybrid orbitals.
One of the remaining p orbital for each carbon overlap to form a pi
bond. A pi bond consists of two parts where bonding electrons are suppose
to be located. A picture depicting the sigma and pi bonds in ethene from
the same source as previous picture is shown on the right.
Carbon atoms make use of sp2 hybrid orbitals not only
in ethene, but also in many other type of compounds. The following are some
of these compounds:
| Formaldhyde | Ketene | Ethylaldehyde | Acetic acid | Benzene | Others |
|---|---|---|---|---|---|
| H \ C=O / H | H \ C=C=O / H | CH3 \ C=O / H | CH3 \ C=O / O-H | CH / \\ HC CH || | HC CH \ // CH | Arromatic compounds Graphite Fullerenes |
During the lecture on covalent bonding, we can illustrate how atomic orbitals overlap in the formation of bonds. Here, we can only show you the nice picture as a result.
| H H \ / H--C---C--H / \ H H |
|---|
Diamond is a crystal form of elemental carbon, and the structure is
particularly interesting. In the crystal, every carbon atom is bonded
to four other carbon atoms, and the bonds are arranged in a tetrahedral
fashion. The bonding, no doubt, is due to the sp3 hybrid
orbitals. The bondlength of 154 pm is the same as the C-C bondlength
in ethane, propane and other alkanes.
An idealized single crystal of diamond is a gigantic molecule, because all the atoms are inter-bonded. The bonding has given diamond some very unusual properties. It is the hardest stone, much harder than any thing else in the material world. It is a poor conductor, because all electrons are localized in the chemical bonds. However, diamond is an excellent heat conductor. A stone made of pure carbon is colorless, but the presence of impurities gives it various colors. The index of refraction is very high, and their glitter (sparkle or splendor) has made them the most precious stones.
| Systematic name | Ethane | Ethene | Ethyne |
|---|---|---|---|
| Hybrid orbitals of C | sp3 | sp2 | sp |
| Structural formula | H H \ / H--C---C--H / \ H H | H H \ / C=C / \ H H | H-CºC-H |
| C-C Bondlength pm | 154 | 134 | 120 |
| C-H Bondlength pm | 112 | 110 | 106 |
| H-C-C bond angle ° | 111 | 121 | 180 |
| C-C bond energy kJ/mol | 368 | 611 | 820 |
| C-H bond energy kJ/mol | 410 | 451 | 536 |
Discussion -
Linear -C- bonds due to sp hybridized orbitals.
This molecule is linear, and it consists of 3 sigma,
s, bonds, and two pi
p, bonds. Compare the bonding of this with
CºO, H-CºN,
CH3-CºN
Discussion -
Planar -C< bonds due to sp2 hybridized orbitals.
Another of p orbital is used for the pi,
p, How many sigma and pi bonds does this
molecule have? Do all atoms in this molecule lie on the same plane?
Discussion -
Tetrahedral arrangement around C is due to sp3
hybridized orbitals.
Discussion -
Tetrahedral arrangement around C is due to sp3
hybridized orbitals.
Discussion -
The bondlength decreases as the bond order increases.
Discussion -
Recognize the type of bonding is important.
Discussion -
The structure is shown below. Can you sketch a bonding structure
for caffeine? How many carbon atoms makes use of sp2 hybrid
orbitals?