As defined, the lattice energy is positive, because energy is always required to separate the ions. For the reverse process, the energy released is called energy of crystallization, Ecryst.
Values of lattice energies for various solids have been given in literature, especially for some common solids. Some are given here.
| Solid | U | Solid | U | Solid | U | Solid | U |
|---|---|---|---|---|---|---|---|
| LiF | 1036 | LiCl | 853 | LiBr | 807 | LiI | 757 |
| NaF | 923 | NaCl | 786 | NaBr | 747 | NaI | 704 |
| KF | 821 | KCl | 715 | KBr | 682 | KI | 649 |
| -- | |||||||
| MgF2 | 2957 | MgCl2 | 2526 | MgBr2 | 2440 | MgI2 | 2327 |
-----------Na+ + Cl(g)--------
|
| |-349
|496+244/2 ¯
| Na+(g) + Cl-(g)
| |
Na(g) + 0.5Cl2(g) |
|
|108 |
| |Ecryst= -788
Na(s) + 0.5Cl2(l) |
| |
|-411 |
¯ ¯
-------------- NaCl(s) --------------
Ecryst = -411-(108+496+244/2)-(-349) kJ/molDiscussion
The value calculated for U depends on the data used.
Data from various sources differ slightly, and so is the result.
The lattice energies for NaCl most often quoted in other texts is
about 765 kJ/mol.
Compare with the method shown below
| Na(s) + 0.5 Cl2(l) ® NaCl(s) | - 411 | Hf |
| Na(g) ® Na(s) | - 108 | -Hsub |
| Na+(g) + e ® Na(g) | - 496 | -IP |
| Cl(g) ® 0.5 Cl2(g) | - 0.5 * 244 | -0.5*D |
| Cl-(g) ® Cl(g) + 2 e | 349 | -EA |
| Add all the above equations leading to | ||
| Na+(g) + Cl-(g) ® NaCl(s) | -788 kJ/mol = Ecryst | |
As an example, let us consider the the NaCl crystal. In the following
discussion, assume r be the distance between Na+ and
Cl- ions. The nearest neighbors of Na+ are 6
Cl- ions at a distance
Ö1r, 12 Na+ ions at
a distance Ö2r, 8 Cl-
at Ö3r, 6 Na+
at Ö4r, 24 Na+
at Ö5r, and so on.
Thus, the energy due to one ion is
z2e2 6 12 8 6 24
E = - ---- [ -- - -- + -- - -- + -- ...]
4peor Ö1 Ö2 Ö3 Ö4 Ö5
| Solid | M | A : C | Type |
|---|---|---|---|
| NaCl | 1.747558 | 6 : 6 | Rock salt |
| CsCl | 1.747558 | 8 : 8 | CsCl type |
| CaF2 | 2.51939 | 8 : 4 | Fluorite |
| TiO2 | 2.408 | 6 : 3 | Rutile |
| Al2O3 | 4.1719 | 6 : 4 | Corundum |
There are other factors to consider for the evaluation of energy of crystallization, and the treatment by M. Born led to the formula for the evaluation of crystallization energy Ecryst, for a mole of crystalline solid:
N z2e2 1
Ecryst = - ------ ( 1 - ---)
4peor n
| n = | 5 | 7 | 9 | 10 | 12 |
| e.c. | He | Ne | Ar | Kr | Xe |
The following values of n have been suggested for some common solids:
| n = | 5.9 | 8.0 | 8.7 | 9.1 | 9.5 |
| e.c. | LiF | LiCl | LiBr | NaCl | NaBr |
Example 1
Solution
Using the values giving in the discussion above, the estimation is given by
6.022x1023 /mol (1.6022-19)2 * 1.747558
Ecryst = - -------------------------------------- ( 1 - 1/9.1)
4p * 8.854x10-12 C2/m * 282x10-12 m
= - 766376 J/mol
= - 766 kJ/mol
Discussion
Much more should be considered in order to evaluate the lattice energy
accurately, but the above calculation leads you to a good start.
When methods to evaluate the energy of crystallization or lattice energy lead to reliable values, these values can be used in the Born-Hable cycle to evaluate other chemical properties, for example the electron affinity, which is really difficult to determine directly by experiment.
Discussion -
Corrundum Al2O3 has some covalent character in
the solid as well as the higher charge of the ions.
Skill -
Evaluate the lattice energy and know what values are needed.
Discussion -
This number has not been checked. If you get a different value, please let
me know.